Question

Consider the probability that fewer than 11 out of 149 houses will lose power once a year. Assume the probability that a given house will lose power once a year is 11%.

Approximate the probability using the normal distribution. Round your answer to four decimal places.

Answer 1

Answer:

.0615

Step-by-step explanation:

p=.11

n=149

np=16.39 (which is the mean)

x<11 so 10.5...-999

σ= $\sqrt{16.39(1-.11)}$ =3.81930622

normalcdf(-999,10.5,16.39,3.81930622)

= .0615167786