Question

Under what conditions would the frictional forces be expected to be equal magnitude for a car moving up an incline and a car moving down an incline?

Answer 1

The condition in which the fictional force will be equal to weight of the car is when the car moves at constant speed.

The horizontal component of the force on the car moving on the inclined plan is given as;

$\Sigma F_x = 0\\\\Wsin(\theta) - F_k = ma$

where;

• W is the weight of the car
• $F_k$ is the frictional force between the car and surface of the inclined plane.

when the speed of the car is constant, the acceleration of the car will be zero.

$Wsin(\theta) - F_k = m(0)\\\\Wsin(\theta) = F_k$

Thus, we can conclude that the condition in which the fictional force will be equal to weight of the car is when the car moves at constant speed.

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