Help anyone can help me do this question,I will mark brainlest.
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Given information
Length AB = 6m
Breadth BC = 4m
The area of PQRS is twice the area of ABCD
Firstly find the area of rectangle ABCD
Area of ABCD= Length × Breadth
Area of ABCD= 6 × 4
Area of ABCD = 24 m²
We know that the area of rectangle PQRS is twice the area of rectangle ABCD so we simply double the area of rectangle ABCD
24m² × 2 = 48m²
We need to find 2 numbers which when multiplied give 48 however the 2 numbers that are chosen must be the same amount greater that the lengths of ABCD and divisible by 2 because the path is uniform.
8 × 6 = 48
8 - 6 = 2
6 - 2 = 2
Therefore the length of PQ is 8m and the length of QR is 6m