Question

prove that the value of the expersion y^2-10y+30 can only be a positive number
PLEASE ANSWER ASAP WILL GIVE BRAINLIEST

Answer 1

Answer:

• See below

Step-by-step explanation:

• y² - 10y + 30 =
• y² - 10y + 25 + 5 =
• (y - 5)² + 5

Since (y - 5)² ≥ 0, the expression above is positve:

• (y - 5)² + 5 ≥ 5

Answer 2

Let's factor out

• y²-10y+30
• y²-2(y)(5)+25+5
• (y-5)²+5

(y-5)² has least value as 0

Least value of expression is 0+5=5

It's positive no