1. Heat 3 kg ice from -10 C to 0 C
is sensible heating so
Q = m cp (T2 - T1)
Q = 3 kg (2.09 kJ/kg C) (0 - (-10)) C
Q = 62.7 kJ
2.Melt 3 kg ice at 0 C
requires latent heat so,
Q = m Hfus
Q = 3 kg (333.55 kJ/kg)
Q = 1000.65 kJ
3. Heat 3 kg water from 0 C to 100 C
requires
Q = 3 kg (4.18 kJ/kg C) (100 - 0) C
Q = 1254 kJ
4. Vaporize 3 kg water at 100 C
requires latent heat, so
Q = m Hvap
Q = 3 kg (2258.33 kJ/kg)
Q = 6775 kJ
5. Heat 3 kg steam from 100 C to 110
requires
Q = 3 kg (2.02 kJ/kg C) (110 - 100) C
Q = 60.6 kJ
