Question

. 1
Find f
for the function f.
f(x) = 3x² + 3, x > 0
And find the domain

Answer 1

Answer:

y = $\sqrt{\frac{x-3}{3} }$

Domain = [3, infinity)

Step-by-step explanation:

x = 3y^2 + 3

3y^2 = x - 3

y^2 = (x-3)/3

y = $\sqrt{\frac{x-3}{3} }$