Write an equation for a line perpendicular to y = -5x – 4 and passing through the point (15,5)
![Write an equation for a line perpendicular to y 5x 4 and passing through the point 155 class=](https://us-static.z-dn.net/files/d5e/0c1543dbeee64e05fa53d7a1eb3de314.png)
Answer:
y=1/5x+2
Step-by-step explanation:
In perpendicular lines the slopes are negative reciprocals so the slope of other line is 1/5x
And they intersect at (15,5) to find the y intercept(b)
y=1/5x+b
5=(1/5)(15)+b
5=3+b
b=2