Respuesta :

Answer:

Answer: (, 0) or (-1, 0)

Step-by-step explanation:

From calculation:

[tex]{ \tt{y = - 2x + 3}}[/tex]

• for x intercept, y is zero

[tex]{ \tt{0 = - 2x + 3}} \\ \\ { \tt{x = \frac{2}{3} }} \\ { \boxed{ \rm{( \frac{2}{3}, \: 0) }}}[/tex]

From the table:

[tex] = { \tt{( - 1, \: 0)}}[/tex]

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