Question

Given R=0.0821L⋅atm/mol⋅K, how many moles of gas are in a 1.25 L container at 300K and 2.07 atm?(1 point)

A)0.084 mol


B)0.105 mol


C)0.067 mol


D)9.51 mol

Answer 1

Answer:

B

Explanation:

Answer 2

There are 0.105 moles of gas are in a 1.25 L container.

Given the following data:

• Volume = 1.25 Liters.

• Temperature = 300 K

• Pressure = 2.07 atm

• Ideal gas constant, R = 0.0821L⋅atm/mol⋅K

To find how many moles (number of moles) of gas are in a 1.25 L container, we would use the ideal gas law equation;

$PV = nRT$

Where;

• P is the pressure.

• V is the volume.

• n is the number of moles of substance.

• R is the ideal gas constant.

• T is the temperature.

Making n the subject of formula, we have;

$n = \frac{PV}{RT}$

Substituting the given parameters into the formula, we have;

$n = \frac{2.07(1.25)}{0.0821(300)}\\\\n = \frac{2.5875}{24.63}$

Number of moles, n = 0.105 moles.

Therefore, there are 0.105 moles of gas are in a 1.25 L container.

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