The cyclist and the car will intersect at 11:50 AM.
To determine the approximate time and place at which the car and the cyclist passed each other the following calculation must be performed:
-The advance of each of the parts must be calculated, and the point where said movement coincides.
- Cyclist =
- Point 0 at 11:00 A.M. --- Stops at 12:30 P.M. having circulated at 10 km / h, that is, it traveled about 15 km (12:30 - 11:00 = 1:30 (1.5)).
- After half an hour of rest, it continues on its way from 1:00 p.m., arriving at its destination at 2:30 p.m.
- If in 60 minutes it travels 10 km, in 6 minutes it travels 1 km, and per minute it travels 0.16 km.
- Car =
- Point 0 at 11:30 AM --- Speed of 50 km / h
- In half an hour it travels 25 km. In 6 minutes it travels 5 km, and per minute it travels 0.83 km. In total it takes 36 minutes to reach Newcastle at 12:06 P.M.
- 11:30 =
- Cyclist = 30 - 10 = 20
- Car = 0
- 11:36 =
- Cyclist = 20 - 1 = 19
- Car = 5
- 11:42 =
- Cyclist = 18
- Car = 10
- 11:48 =
- Cyclist = 17
- Car = 15
- 11:49 =
- Cyclist = 17 - (1/6) = 16.83
- Car = 15 + (5/6) = 15.83
- 11:50 =
- Cyclist = 16.83 - (1/6) = 16.66
- Car = 15.83 + 0.83 = 16.66
Therefore, the cyclist and the car will intersect at 11:50 AM.
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