Answer:
Step-by-step explanation:
Let cost of items for 10 bags be represented by x
Cost of 1 bag=$ 0.75
Cost of 10 bags=$ (0.75×10)
= $ 7.5
Total cost of 10 bags with items in them=$(7.5+x)
Marcus cannot spend more than $50.
i.e. 7.5+x≤50
Subtracting both sides by 7.5
x≤42.5
Most Marcus can spend for items in 10 bags=$42.5
Most Marcus can spend for items in 1 bag=$(42.5/10)=$4.25
Hence, most Marcus can spend on the items for each bag is:
$4.25
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