Question

Find an equation of the line perpendicular to the graph of 14x – 7y = 4 that passes through the point at (2, – 9).
C D E
a.
y = 2x - 8
C.
1
y = -X-8
2
b.
d.
1
y = -x + 8
y=
X-8

Answer 1

Answer:

y = -1/2x-8

Step-by-step explanation:

14x - 7y = 4 and (2,-9)

14x - 4 = 7y

14/7x - 4/7 = y

Slope = 2

Slope of the perpendicular line: -1/2

b = -9 - (-1/2)(2)

b = -9 +1

b = -8

y = -1/2x - 8