Answer:
The equation of line parallel to y=5x+2 that passes through the point with coordinates (−2,1) is:
y=5x+11y=5x+11
Step-by-step explanation:
Given line is:
y=5x+2
Given equation is in slope-intercept form, the coefficient of x will be the slope of line
So slope is 5
As parallel lines have equal slopes the required line will also have slope 5.
Slope-intercept form is:
y=mx+b
Putting the value of slope
y=5x+b
To find the value of b, putting (-2,1) in equation
\begin{gathered}1=(5)(-2)+b\\1=-10+b\\b=1+10\\b=11\end{gathered}
1=(5)(−2)+b
1=−10+b
b=1+10
b=11
Putting the values of b and m
y=5x+11y=5x+11
The equation of line parallel to y=5x+2 that passes through the point with coordinates (−2,1) is:
y=5x+11y=5x+11
Keywords: Equation of line, Slope-intercept form
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