Question

A light bulb has a resistance of 5 ohms and a maximum current of 10 A. How much voltage can be applied before the bulb will break?​

Answer 1

The maximum voltage which can be applied before the bulb will break is 50 Volts.

Given the following data:

• Resistance of light bulb = 5 Ohms

• Current = 10 Amps.

To find how much voltage can be applied before the bulb will break, we would apply Ohm's law:

Ohm's law states that at constant temperature, the current flowing through an electrical circuit is directly proportional to the voltage applied across the two terminals of the circuit and it's inversely proportional to the resistance in the electrical circuit.

Mathematically, Ohm's law is given by the formula;

$V = IR$

Where;

• V is voltage measured in voltage.

• I is current measured in amperes.

• R is resistance measured in ohms.

Substituting the given parameters into the formula, we have;

$Voltage = 10$ × $5$

Voltage = 50 Volts.

Therefore, the maximum voltage which can be applied before the bulb will break is 50 Volts.

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