Using the normal distribution, it is found that 10.56% of the apples weigh less than Jermaine's apple.
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In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
In this problem:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{0.25 - 0.33}{0.06}[/tex]
[tex]Z = -1.25[/tex]
[tex]Z = -1.25[/tex] has a p-value of 0.1056.
0.1056 x 100% = 10.56%.
10.56% of the apples weigh less than Jermaine's apple.
A similar problem is given at https://brainly.com/question/13411796