Question

A bag contains three counters:
one red,onegreen,and one blue.
what is the probability of drawing a blue counter in the first draw?​

Answer 1

Answer:

1/3

Step-by-step explanation:

(number of favoured outcomes)/(total possible outcomes)

here number of favoured choices is 1 and the total number of choices is 3

Answer 2

The $PROBABILITY$ of drawing a $BLUE$ counter is

$\frac{1}{3}$ because we have 3 counters, and only 1 of them is blue.

Hope it helps!

◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦

◦    Comment:               ◦

◦     Please                    ◦

◦          Mark                   ◦

◦          Brainliest           ◦

◦                :)                 ◦

◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦ ◦