Question

Given that $c=\frac{2d+1}{3d-1}$,
1. calculate the value of c when d = $\frac{1}{4}$
2. express d in terms of c

Answer 1

Answer:

C = -6

Step-by-step explanation:

C = [2×1/4 + 1] ÷ [3×1/4 -1 ]

C = 3/2 ÷ -1/4

C = 3/2 × -4 = -6

C = 2d + 1 / 3d - 1

So, d = ( C + 1 ) / ( 3C - 2 )

Answer 2

1.

$c = \frac{2d + 1}{3d - 1}$

$c = \frac{(2 (\frac{1}{4})) + 1}{(3 ( \frac{1}{4})) - 1 }$

$c = \frac{ \frac{1}{2} + 1}{ \frac{3}{4} - 1}$

$c = \frac{ \frac{1}{2} + \frac{2}{2} }{ \frac{3}{4} - \frac{4}{4} }$

$c = \frac{ \frac{1 + 2}{2} }{ \frac{3 - 4}{4} }$

$c = \frac{ \frac{3}{2} }{ \frac{ - 1}{4} }$

$c = \frac{3}{2} \times \frac{4}{ - 1}$

$c = \frac{3}{1} \times \frac{2}{ - 1}$

$c = \frac{6}{ - 1}$

$c = - 6$