Question

one atom of gold weighs 3.27 x 10-13 ng. how many gold atoms are in 1.0 g of gold?

Answer 1

Answer:

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Explanation:

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Answer 2

The number of atoms in 1 g of gold is 3.06×10²¹ atoms

From the question given above, the following data were obtained:

• 1 atom of gold = 3.27×10¯¹³ ng

• 1 g of gold =?

Next, we shall covert 3.27×10¯¹³ ng  to grams. This can be obtained as follow:

1 ng = 1×10¯⁹ g

Therefore,

3.27×10¯¹³ ng = 3.27×10¯¹³ × 10¯⁹

3.27×10¯¹³ ng = 3.27×10¯²² g

Finally, we shall determine the number of atoms in 1 g of gold.

3.27×10¯²² g of gold = 1 atom

Therefore,

1 g of gold = 1 / 3.27×10¯²²

1 g of gold = 3.06×10²¹ atoms

Thus, there are 3.06×10²¹ atoms in 1 g of gold.

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