Question

Determine the volume (in mL) of water that needs to be added to 25.0 mL of a 0.250 M NaBr to produce a 0.0435 M solution. Assume the volumes are additive.

Answer 1

The volume of water added to make the diluted solution is 118.68 mL.

To solve this question, we'll begin by calculating the volume of the diluted solution. This can be obtained as follow:

Volume of stock solution (V₁) = 25 mL

Molarity of stock solution (M₁) = 0.250 M

Molarity of diluted solution (M₂) = 0.0435 M

Volume of diluted solution (V₂) =?

The volume of the diluted solution can be obtained as follow:

M₁V₁ = M₂V₂

0.25 × 25 = 0.0435 × V₂

6.25 = 0.0435 × V₂

Divide both side by 0.0435

V₂ = 6.25 / 0.0435

V₂ = 143.68 mL

Thus, the volume of the diluted solution is 143.68 mL

Finally, we shall determine the volume of water added to make the diluted solution.

Volume of stock solution (V₁) = 25 mL

Volume of diluted solution (V₂) = 143.68 mL

Volume of water added =?

Volume of water added = (Volume of diluted solution) – (Volume of stock solution)

Volume of water added = 143.68 – 25

Volume of water added = 118.68 mL

Therefore, the volume of water added to make the diluted solution is 118.68 mL

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