The electric field due to a point charge of 20uC at a distance of 1 meter away from it is 180000 [tex]\frac{N}{C}[/tex].
First, you have to know that the space surrounding a load suffers some kind of disturbance, since a load located in that space will suffer a force. The disturbance that this charge creates around it is called an electric field.
In other words, an electric field exists in a certain region of space if, when introducing a charge called witness charge or test charge, it undergoes the action of an electric force.
The electric field E created by the point charge q at any point P, located at a distance r, is defined as:
[tex]E=K\frac{q}{r^{2} }[/tex]
where K is the constant of Coulomb's law.
In this case, you know:
Replacing in the definition of electric field:
[tex]E=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{20x10^{-6} C}{(1 m)^{2} }[/tex]
Solving:
E=180000 [tex]\frac{N}{C}[/tex]
Finally, the electric field due to a point charge of 20uC at a distance of 1 meter away from it is 180000 [tex]\frac{N}{C}[/tex].
Learn more:
