How long does it take electrons to get from
the car battery to the starting motor? Assume
the current is 134 A and the electrons travel
through copper wire with cross sectional area
38.9 mm- and length 92.2 cm. The mass den-
sity of copper is 8960 kg/m and the molar
mass is 63.5 g/mol. Avogadro's number is
6.022 x 10 . Asume that each copper atom
contributes one conduction electron.
Answer in units of min.

Respuesta :

We need to find the time it takes an electron to move in the given circuit.

The time taken for electrons to reach the starting motor from the battery is 60.65 minutes.

I = Current = 134 A

[tex]N_A[/tex] = Avogadro's number = [tex]6.022\times 10^{23}\ \text{mol}^{-1}[/tex]

A = Area = [tex]38.9\ \text{mm}^2[/tex]

L = Length = 92.2 cm

[tex]\rho[/tex] = Density of copper = [tex]8960\ \text{kg/m}^3[/tex]

M = Molar mass of copper = 63.5 g/mol

[tex]n_v[/tex] = Number of valence electrons of copper = 1

e = Charge of electron = [tex]1.6\times 10^{-19}\ \text{C}[/tex]

Number of charge carriers per unit volume is given by

[tex]n=\dfrac{\rho N_An_v}{M}\\\Rightarrow n=\dfrac{8960\times 6.022\times 10^{23}\times 1}{63.5\times 10^{-3}}\\\Rightarrow n=8.497\times 10^{28}\ \text{m}^{-3}[/tex]

Time taken is given by

[tex]t=\dfrac{LAne}{I}\\\Rightarrow t=\dfrac{92.2\times 10^{-2}\times 38.9\times 10^{-6}\times 8.497\times 10^{28}\times 1.6\times 10^{-19}}{134}=3638.83\ \text{s}\\\Rightarrow t=\dfrac{3638.83}{60}=60.65\ \text{minutes}[/tex]

The time taken for electrons to reach the starting motor from the battery is 60.65 minutes.

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