The equation of the line in standard form is 5y=19x - 116
The standard form of a linear equation is given by:
y = mx + b
Where y is a dependent variable, x is an independent variable, m is the slope of the line (the rate of change), b is the y intercept (that is the initial value of y).
Since the line passes through the point (4, -8) and (9, 11), hence the equation of the line is:
[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-(-8)=\frac{11-(-8)}{9-4} (x-4)\\\\y+8=\frac{19}{5}(x-4)\\\\5y+40=19x-76 \\\\5y=19x-116[/tex]
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