Question

A tablespoon full glucose weighs 1.8 gram. Calculate the followings:
(a) No. of males of glucose present,
(b) No. of hydrogen atoms,
(C) No. of oxygen atoms.


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Answer 1

Explanation:

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Answer 2

• Given mass=1.8g
• Molar mass of glucose=180g/mol

No of moles=Given mass /molar mass

$\\ \sf\longmapsto \dfrac{1.8}{180}=0.01mol$

Now

• Moles of Carbon=6(0.01)=0.06mol
• Moles of Oxygen=6(0.01)=0.06mol
• Moles of hydrogen=12(0.01)=0.12mol

No of atoms=No of moles×Avagadro no

#No of hydrogen atoms

$\\ \sf\longmapsto 0.12(6.023\times 10^{23})=0.723\times 10^{23}atoms=7.23\times 10^{22}atoms$

#No of Oxygen atoms

$\\ \sf\longmapsto 0.06(6.023\times 10^{23})=3.61\times 10^{22}atoms$