Question

A calibration curve is prepared to measure Fe2+ concentrationof serum ion, and the best-fit line had the equation y= 0.0042x + 0.012. Calculate the Fe2+ concentration for Patient A. Note the concentration units of the standards were micrograms per deciliter (µg/dL)

Patient A: Absorbance = 0.872

Answer 1

The concentration of Fe²⁺ in a sample with an absorbance of 0.872, determined through the calibration curve $y = 0.0042x + 0.012$, is 205 µg/dL.

In many analytical techniques, it is common to prepare calibration curves from standard solutions to determine the concentration of an unknown analyte. In this problem, we want to determine the concentration of Fe²⁺ and the following linear regression is made:

$y = 0.0042x + 0.012$

where,

• y: absorbance of the sample

• x: concentration of the analyte (in µg/dL)

The concentration of Fe²⁺ in a sample with an absorbance of 0.872 is:

$y = 0.0042x + 0.012\\x = \frac{y - 0.012}{0.0042} = \frac{0.872 - 0.012}{0.0042} = 205 \mu g/dL$

The concentration of Fe²⁺ in a sample with an absorbance of 0.872, determined through the calibration curve $y = 0.0042x + 0.012$, is 205 µg/dL.

You can learn more about calibration curves here: https://brainly.com/question/15061774