Question

a ball of mass 0.80 kg moving at a speed of 2.5 m/s along a straight line collided with a mass 2.5 kg which was initially stationary. As a result of the collision, the 2.5 g ball was given a velocity of 1.0 m/s along the same line. Calculate the speed and irection of the 0.80 kg ball immediately after the collision.​

Answer 1

The speed of the 0.8 kg ball immediately after collision is 0.625 m/s in opposite direction to the stationary ball.

The given parameters;

• mass of the ball, m₁ = 0.8 kg
• speed of the ball, u₁ = 2.5 m/s
• mass of the object at rest, m₂ = 2.5 kg
• final velocity of the object at rest, v₂ = 1 m/s

Let the final velocity of the 0.8 kg ball immediately after collision = v₁

Apply the principle of conservation of linear momentum;

m₁u₁ + m₂u₂ = m₁v₁  +  m₂v₂

(0.8 x 2.5) + (2.5 x 0) = (0.8)v₁  +  2.5(1)

2 = 2.5 + (0.8)v₁

-0.5 = (0.8)v₁

$v_1 = \frac{-0.5}{0.8} \\\\v_1 = -0.625 \ m/s$

Thus, the speed of the 0.8 kg ball immediately after collision is 0.625 m/s in opposite direction to the stationary ball.

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