Question

What is the solution set of the equation using the quadratic formula?
x^2+2x+10=0

A.) {−1+3i, −1−3i}
B.) {−2+6i, −2−6i}
C.) {2i, −4i}
D.) {−1}

Answer 1

Answer:

$\frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a} \\ \frac{ - 2 \pm \sqrt{4 - 4(1)(10)} }{2} \\ = \frac{ - 2 \pm \sqrt{ - 36} }{2} \\ = \frac{ - 2 \pm 6i }{2} \\ - 1 \pm3i \\ so \: the \: answer \: is \: A$