The empirical formula of the compound Y is IrF₆
From the question given above, the following data were obtained:
Iridium (Ir) = 62.75%
Fluorine (F) = 37.25%
Empirical formula =?
The empirical formula of the compound Y can be obtained as follow:
Ir = 62.75%
F = 37.25%
Divide by their molar mass
Ir = 62.75 / 192 = 0.3268
F = 37.25 / 19 = 1.9605
Divide by the smallest
Ir = 0.3268 / 0.3268 = 1
F = 1.9605 / 0.3268 = 6
Therefore, the empirical formula of the compound Y is IrF₆
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