Respuesta :
The mass of the brass sample is 34.89 g
We'll begin by calculating the heat gained by the water. This can be obtained as follow:
Mass of water (M) = 50.15 g
Initial temperature of water (T₁) = 23.5 °C
Final temperature of water (T₂) = 27.2 °C
Change in temperature of water (ΔT) = T₂ – T₁
Change in temperature of water (ΔT) = 27.2 – 23.5
Change in temperature of water (ΔT) = 3.7 °C
Specific heat capacity of water (C) = 1 cal/gºC
Heat gained by water (Q) =?
Q = MCΔT
Q = 50.15 × 1 × 3.7
Q = 185.555 calories
Thus, the heat gained by the water is 185.555 calories
Next, we shall determine the heat lost by the metal. This can be obtained as follow:
Heat lost by metal = Heat gained by water
Heat gained by water = 185.555 calories
Thus,
Heat lost by metal = Heat gained by water = 185.555 calories
Recall:
Heat lost is always negative.
Therefore,
Heat lost by metal = –185.555 calories
Finally, we shall determine the mass of the brass sample. This can be obtained as follow:
Specific heat capacity of metal (C) = 0.092 cal/g°C
Initial temperature of metal (T₁) = 85.0 °C
Final temperature of metal (T₂) = 27.2 °C
Change in temperature of metal (ΔT) = T₂ – T₁
Change in temperature of meta (ΔT) = 27.2 – 85
Change in temperature of metal (ΔT) = –57.8 °C
Heat lost by metal = –185.555 calories
Mass of brass (M) =?
Q = MCΔT
–185.555 = M × 0.092 × –57.8
–185.555 = –5.3176M
Divide both side by –5.3176
[tex]M =\frac{-185.555}{-5.3176}[/tex]
Mass of metal = 34.89 g
Therefore, the mass of the brass sample is 34.89 g
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