Question

When 24.0 V is applied to a
capacitor, it stores 3.92 x 10-4 J of
energy. What is the capacitance?

No links please

Answer 1

Answer:

Explanation:

energy of capacitor E = 1/2 * C*V2

C = E * 2/V2

C = 0.0136 * 10-4 J = 1.36 * 10-6 F

SO

COEFFICIENT = 1.36

EXPONENT = -6