Respuesta :
Answer:
No solutions
Step-by-step explanation:
First, distribute on the left side of the equation:
2 ( x + 1 ) = 2x - 5
2x + 2 = 2x - 5
Subtract 2x from each side:
2x + 2 = 2x - 5
2 = -5
Add 5 to each side:
2 = -5
7 = 0
7 ≠ 0
There are no solutions
Hii :))
[tex] \tt \: 2(x + 1) = 2x + 5 \\ \tt \: 2x + 2 = 2x - 5 \\ \tt \: 2x - 2x = - 5 - 2 \\ \underline {\underline{\tt \: 0 \: \bcancel{=} \: 7x}}[/tex]
Since LHS isn't equal to RHS, the equation will have 2) no solution.
__________________
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