Respuesta :

Answer:

No solutions

Step-by-step explanation:

First, distribute on the left side of the equation:

2 ( x + 1 ) = 2x - 5

2x + 2 = 2x - 5

Subtract 2x from each side:

2x + 2 = 2x - 5

2 = -5

Add 5 to each side:

2 = -5

7 = 0

7 ≠ 0

There are no solutions

Hii :))

[tex] \tt \: 2(x + 1) = 2x + 5 \\ \tt \: 2x + 2 = 2x - 5 \\ \tt \: 2x - 2x = - 5 - 2 \\ \underline {\underline{\tt \: 0 \: \bcancel{=} \: 7x}}[/tex]

Since LHS isn't equal to RHS, the equation will have 2) no solution.

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