Value of ∠5 is 140°
Given that;
∠5 and ∠6 are a linear pair
∠5 = (4x - 20)°
∠6 = x°
Find:
Value of ∠5
Computation:
We know that, sum of linear pair angle is 180°
So,
∠5 + ∠6 = 180°
(4x - 20)° + x° = 180°
4x - 20 + x = 180
5x - 20 = 180
5x = 180 + 20
5x = 200
x = 200 / 5
x = 40
So,
Value of ∠5 = (4x - 20)°
Value of ∠5 = 4(40) - 20
Value of ∠5 = 160 - 20
Value of ∠5 = 140°
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