The distance between the points ( -8, -9), and (-4, -10) is √ 15 units.
The shortest distance (length of the straight line segment's length connecting both given points) between points ( p,q) and (x,y) is:
D = √[(x-p)² + (y-q)²] units.
Given the points ( -8, -9), and (-4, -10)
Finding the distance between the points ( -8, -9), and (-4, -10)
(x₁, y₁) =( -8, -9)
(x₂, y₂) = (-4, -10)
The distance will be;
D = √[(x-p)² + (y-q)²] units.
Substittue;
D = √[(-4- (-8))² + (-10 -(-9))²] units.
D = √[(4)² + (1)²] units.
D = √[16+ 1] units.
D = √ 15
Thus, the distance between the points ( -8, -9), and (-4, -10) is √ 15 units.
Learn more about distance between two points here:
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