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[tex]\sf \: 1). \: 2, \: 4, \: 6, \: 8, \: \boxed{ 10}, \: \boxed{12}, \: \boxed{14}[/tex]

[tex]\sf \: 2.) \: 3, \: 6, \: 9, \: 12, \boxed{15}, \boxed{18}, \boxed{21}[/tex]

[tex]\sf \: 3.) \: 3, \: 5, \: 7, \: 9, \boxed{11}, \boxed{13}, \boxed{15}[/tex]

[tex]\sf \: 4.) \displaystyle \frac{2}{3} , \: \displaystyle \frac{3}{4} , \: \displaystyle \frac{4}{5} , \: \boxed{\displaystyle \frac{5}{6} }, \: \boxed{ \displaystyle \frac{6}{7} }, \: \boxed{\displaystyle \frac{7}{8} }[/tex]

Explanation

  • On number 1, notice that the first 4 portions of the sequence added +2 per term. This concludes that item no.1 counts +2 per term in the sequence.

  • On number 2, notice that the first 4 portions of the sequence added +3 per term. This concludes that item no.2 counts +3 per term in the sequence.

  • On number 3, notice that the first 4 portions of the sequence added +2 per term. This concludes that item no.3 counts +2 per term in the sequence starts with 3.

  • On number 4, notice that the numerator and denominator increase +1 per term alternately both. This concludes that item no.4 counts +1 on both numerator and denominator of the fraction.

Goodluck! :D

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