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When a piece of aluminum is placed in a 25-mL graduated cylinder that contains 10.5 mL of water, the water level rises to 13.5 mL. What is the mass of the aluminum?

Respuesta :

Answer:

Mass of the sample of aluminium = m

Volume of the aluminium = V

Density of the aluminum = d = 2.7 g/mL

Initial level of water mark in cylinder = 10.0 mL

Final level of water after sample is immersed = 18.0 mL

Volume occupied by the sample = V = 18.0 mL - 10.0 mL = 8.0 mL

Explanation:

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Answer:

The mass of the aluminium sample is 21.6 grams.

Explanation:

Mass of the sample of aluminium = m

Volume of the aluminium = V

Density of the aluminum = d = 2.7 g/mL

Initial level of water mark in cylinder = 10.0 mL

Final level of water after sample is immersed = 18.0 mL

Volume occupied by the sample = V = 18.0 mL - 10.0 mL = 8.0 mL

The mass of the aluminium sample is 21.6 grams.

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