Question

Giving brainliest or what ever it’s called to who can solve this for me

Answer 1

• Its a cuboid .Opposite sides,Planes,angles are same.

HERE

• BD=4
• CD=3

In. triangle BDC

Using Pythagorean theorem

$\\ \sf\longmapsto CB^2=BD^2+CD^2$

$\\ \sf\longmapsto CB^2=3^3+4^2$

$\\ \sf\longmapsto CB^2=9+16$

$\\ \sf\longmapsto CB^2=25$

$\\ \sf\longmapsto CB=\sqrt{25}$

$\\ \sf\longmapsto CB=5$

Answer 2

Step-by-step explanation:

Solution,

In triangle BCD

CD = b = 3

BD = p = 4

CB = h = ?

By using Pythagoras theorem,

h²=p²+b²

(CB)²=(BD)²+(CD)²

(CB)²=(4)²+(3)³

(CB)²=16+9

(CB)²=25

CB=√25

CB=5