We have that The specific gravity of 45.0mL of this liquid is
[tex]g=0.7493[/tex]
From the question we are told
Generally the equation for the specific gravity is mathematically given as
[tex]g=\frac{ density of liquid }{ density of water}[/tex]
Therefore
[tex]g=\frac{0.748 }{ 0.9982}\\\\g=0.7493[/tex]
Therefore
The specific gravity of 45.0mL of this liquid is
[tex]g=0.7493[/tex]
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