There are 60 ordered arrangements of 5 objects k, n, o, p, and q choosing 3 at a time without repetition.
Given: There are 5 objects k, n, o, p, and q.
To find the number of ordered arrangements of 5 objects k, n, o, p, and q choosing 3 at a time without repetition.
Th number of permutation of n things taken r at a time is
[tex]P(n,r)=\frac{n! }{(n-r)! }[/tex]
So, substitute the values [tex]n=5,r=3[/tex] in the formula
[tex]P(5,3)=\frac{5! }{(5-3)! }\\=\frac{5! }{(2)! }\\=\frac{5.4.3.2! }{(2)! }\\=60[/tex]
Learn more:https://brainly.ph/question/13922408