Answer:
All in 3 significant figures
Q1: 38.8 m/s
Q2: 40.8 m/s
Q3: 80 m
Q4: 1.23 m/s^2
Q5: 12.2 m/s
Explanation:
Use the equation [tex]v^{2}[/tex] = [tex]u^{2}[/tex] + 2as where
v = final velocity
u = initial velocity
a = acceleration
s = distance travelled
Q1: Find final speed (v):
v^2 = 0^2 + (2 x 2.5 x 300)
v^2 = 1500
v = 38.8 m/s
Q2: Find final speed (v)
*Make sure to convert 1km into standard units (m)
*1km = 1000m
v^2 = 8^2 + (2 x 0.8 x 1000)
V^2 = 40.8 m/s
Q3: Find distance travelled (s)
First rearrange the equation to find s:
v^2 = u^2 + 2as
s = (v^2 - u^2) / 2a
Then solve with given values
s = (7^2 - 3^2) / (2 x 0.25)
s = 80 m
Q4: Find acceleration (a)
*Blurry picture so values may be off
*Make sure to convert km to standard units (m)
*2km = 2000m
First rearrange the equation to find a:
v^2 = u^2 + 2as
a = (v^2 - u^2) / 2s
Then solve with given values
a = (70^2 - 0^2) / (2 x 2000)
a = 1.23 m/s^2
Q5: Find final speed (v)
v^2 = 0^2 + (2 x 0.75 x 100)
v^2 = 150
v = 12.2 m/s
Note: When converting v^2 to v you must square both sides ([tex]\sqrt{x}[/tex])
