The values of the angles a - f are
a = 47°
b = 86°
c = 47°
d = 47°
e = 86°
f = 8°
Calculating angles in a circle
From the question, we are to determine the values of angles a - f.
In the diagram,
/AO/ = /BO/ (They are radii of the circle)
Then,
ΔAOB is an isosceles triangle
∴ a = 47° (Base angles of an isosceles triangle)
b + a + 47° = 180° (Sum of angles in a triangle)
b + 47° + 47° = 180°
b + 94 = 180°
b = 180° - 94°
b = 86°
Since AB = CD
Then, ΔAOB and ΔCOD are similar triangles
By comparison,
c = 47°
c = d (Base angles of an isosceles triangle)
d = 47°
e = 86° (By comparison)
b + f + e = 180° (Sum of angles on a straight line)
86° + f + 86° = 180°
f + 172° = 180°
f = 180° - 172°
f = 8°
Hence, the values of the angles a - f are
a = 47°
b = 86°
c = 47°
d = 47°
e = 86°
f = 8°
Learn more on Calculating angles in a circle here: https://brainly.com/question/17074363