Question

f f(x) = 3x2 + 1 and g(x) = 1 – x, what is the value of (f – g)(2)?
12
14
36
38

Answer 1

f-g = 3x^2+1-(1-x) = 3x^2+x
(f-g)(2)=3*2^2 + 2 = 14

Answer 2

Answer:

B.14

Explanation:

We are given that

$f(x)=3x^2+1$

$g(x)=1-x$

We have to find the value of (f-g)(2)

$(f-g)(x)=f(x)-g(x)$

$(f-g)(x)=3x^2+1-(1-x)=3x^2+1-1+x=3x^2+x$

Substitute x=2

Then, we get

$(f-g)(2)=3(2)^2+2$

$(f-g)(2)=12+2=14$

Hence, the value of (f-g)(2)=14