Explanation:
We have to first write an equation for the reaction that occurs:
H₃PO₄ + 3 NH₃ → (NH₄)₃PO₄
Now, moles of H₃PO₄ = mass ÷ molar mass
= 8.29 g ÷ 97.99 g/mol
= 0.0846 mol
Now, the mole ratio of H₃PO₄ : (NH₄)₃PO₄ is 1 : 1
∴ since moles of H₃PO₄ = 0.0846 mol
then moles of (NH₄)₃PO₄ = 0.0846 mol
∴ the mass of (NH₄)₃PO₄ produced = mol × molar mass
= 0.0846 mol × 149.09 g/mol
= 12.6 g