Question

Un cazador ubicado en la coordenada C(-5,8) y un venado ubicado en las coordenadas V(7,1) escala 1 unidad= 10m determina los metros de separación entre el cazador u el venado en línea recta

Answer 1

The meters of separation between the hunter and the deer in a straight line is 138.9m

In order to calculate the required distance, we will be using the distance formula expressed as:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Given the coordinate of the distance C(-5, 8) and V(7, 1), substitute the coordinates into the formula as shown:

$D=\sqrt{(7-(-5))^2+(1-8)^2}\\D=\sqrt{(12)^2+(-7)^2}\\\\D=\sqrt{144+49}\\D = \sqrt{193}\\D = 13.89units$

Convert the distance to meters

Since 1unit = 10m

13.89units = 138.9m

Hence the meters of separation between the hunter and the deer in a straight line is 138.9m

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