Answer:
[tex]\displaystyle a = -2.5 \text{ m/s$^2$}[/tex]
Explanation:
We can utilize one of the four kinematic equations:
[tex]\displaystyle v_ f = v_i + at[/tex]
Since the car is moving at 5 m/s and comes to a complete stop after two seconds, v_i = 5 m/s, v_f = 0 m/s, and t = 2 s.
Substitute and solve for a:
[tex]\displaystyle \begin{aligned} v_f &= v_i + at \\ \\ (0 \text{ m/s}) &= (5 \text{ m/s}) + a(2\text{ s}) \\ \\ a &= - 2.5\text{ m/s$^2^$} \end{aligned}[/tex]
In conclusion, the acceleration of the car was -2.5 m/s². In other words, it was decelerating at a rate of 2.5 m/s².
