Using the range rule of thumb, it is found that:
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The z-score of a measure X, in a distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
Scores that are significantly low:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]-2 = \frac{X - 19.7}{5.3}[/tex]
[tex]X - 19.7 = -2(5.3)[/tex]
[tex]X = 9.1[/tex]
Scores of 9.1 or lower are significantly low.
Scores that are significantly high:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]2 = \frac{X - 19.7}{5.3}[/tex]
[tex]X - 19.7 = 2(5.3)[/tex]
[tex]X = 30.3[/tex]
Scores of 30.3 or higher are significantly high.
A similar problem is given at https://brainly.com/question/24126815