Question

(7p^(2)+3p)-(5p^(2)+4)
solve for standard form and show how you got it

Answer 1

$\huge \boxed{\mathfrak{Question} \downarrow}$

• $( 7 p ^ { 2 } + 3 p ) - ( 5 p ^ { 2 } + 4 )$. Solve for standard form.

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$( 7 p ^ { 2 } + 3 p ) - ( 5 p ^ { 2 } + 4 )$

To find the opposite of 5p²+4, find the opposite of each term inside the bracket.

$7p^{2}+3p-5p^{2}-4$

Combine 7p² and -5p² to get 2p².

$\boxed{ \boxed{ \bf \: 2p^{2}+3p-4 }}$

Answer 2

Hey there!

Question:-

$\sf \longmapsto(7p^2+3p)-(5p^2+4)$

We need to solve the solution for standard form.

Solution:-

$\sf \: (7p^2+3p)-(5p^2+4)$

Firstly, Distribute the minus symbol :-

$\sf \longmapsto7p {}^{2} +3p+(\red{-1})(5p^2+4)$

$\sf \longmapsto7p^2+3p+\red{-1}(5p^2)+(\red{-1})(4)$

$\sf \longmapsto \: 7p {}^{2} + 3p + ( - 5p {}^{2} + ( - 4)$

Combine Like terms:-

$\sf \longmapsto \:( 7 {p}^{2} + - 5 {p}^{2} ) + (3p + - 4)$

Note that (+) and (-) equals to (-).

$\sf \longmapsto \:( 7 {p}^{2} - 5 {p}^{2} ) + (3p - 4)$

On Simplification:-

$\sf \longmapsto \: {2p}^{2} + 3p - 4$

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Henceforth,The standard form of the algebraic expression is :-

$\boxed{\red{\bf\: 2 {p}^{2} + 3p - 4}}$

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Please let me know if you have any questions.

~MisterBrian