Question

Derivative of 5yx^2 interms of y

Answer 1

Answer:

$y = \frac{1}{5 {x}^{2} }$

Step-by-step explanation:

$5y {x}^{2}$

$5y {x}^{2} =0$

Take other side as zero cause there is no other value.

$\frac{1}{5} \times 5y {x}^{2} = 0 \times \frac{1}{5}$

$y {x}^{2} = \frac{1}{5}$

$\frac{1}{ {x}^{2} \ \: } \times y {x}^{2} = \frac{1}{5} \times \frac{1}{ {x}^{2} }$

$y = \frac{1}{5} \times \frac{1}{ {x}^{2} }$

$y = \frac{1}{5 {x}^{2} }$

Answer 2

Answer:

5yx^2

Here we have to get derivative of  5yx^2 interms of y.

so  we consider the other terms as constant.

5x^2 is constant

derivative of y with respect to y is 1

so final answer= derivative of y with respect to y×constant terms

                        = 1 × (5x^2)

                        =5x^2

Step-by-step explanation: