Question

Note only genius can answer ,are u a genius if yes then solve this problem....when a stone id dropped into a well .sound of the splash was heard only 3 second later .how deep is the well ?Ignore speed of sound.(answer=44.1 m) explain clearly ...is any genius here?​

Answer 1

Answer:

178 ft

let t1 = drop time, let t2 = time for sound to travel up to you, Y = well depth

t1 + t2 = 3.5

Y = 1087 t2 = 16 t1^2

Substitute: t2 = 3.5 - t1

16 t1^2 = 1087 (3.5 - t1)

16 t1^2 = 3804.5 - 1087 t1

16 t1^2 + 1087 t1 - 3804.5 = 0

Solve via quadratic equation: t1 = 3.336 s, t2 = 0.164 s

Y = 178 ft