We have that radioactive power is emitted
x=584.5W/m^2
From the question we are told
Generally the equation for the earths daylight surface disk area is mathematically given as
[tex]A=\pi*r^2\\\\A=\pi*6400^2\\\\A=128679635.1m^2[/tex]
Generally
Energy absorbed = energy emitted
Therefore
[tex]1169 *\pi*r^2=2*\pi*6400^2\\\\x=584.5W/m^2[/tex]
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