Question

Calculate the change in thermal energy of the water in a pond with a mass of 1,000 Kg and a specific heat of 4,184 J/kg °C if the water cools by 1°C
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Answer 1

We will consider that specific heat of any material raises the temperature of 1 kg in 1°C.

Q= m ( Tf - Ti ) C,

where m is mass, Tf is final temperature, Ti is initial temperature and C is the specific heat of the substance.

So, by substituting values, the answer we get is 4184000 J

Hope it helps you...

Answered by Benjemin

Answer 2

The change in thermal energy of the water in a pond is 4,184 kj.

Given to us,

Mass of the water of the pond, m = 1,000 kgs.,

specific heat of the water, C = 4,184  J/kg °C,

change in temperature, ΔT =  1 °C,

As we know, change in heat is given by,

$\bold{Q=m\times C\times \Delta T }$,

where,

m = mass,

C = specific heat,

ΔT = $\bold{(T_f-T_i)}$ = change in temperature.

Substituting the value we get,

$Q=m\times C\times \Delta T\\Q=1,000 \times 4,184\times 1\\Q = 4,184,000\ j\\Q = 4,184\ kj$

Hence, the change in thermal energy of the water in a pond is 4,184 kj.

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