Question

if h(x)=1/4x^4-3x^3, find h(4) PLEASE HELP MEEEEEEE

Answer 1

Step-by-step explanation:

• h(x)=1/4x⁴-3x³

By replacing x with 4, we get

• h(4)=1/4×4⁴-3×4³
• h(4)=1/4×256-3×64
• h(4)=64-192
• h(4)=-128

Answer 2

$\\ \sf\bull\longmapsto h(x)=\dfrac{1}{4}x^4-3x^3$

$\\ \sf\bull\longmapsto h(4)$

$\\ \sf\bull\longmapsto \dfrac{1}{4}4^4-3(4)^3$

$\\ \sf\bull\longmapsto 4^3-3(64)$

$\\ \sf\bull\longmapsto 64-192$

$\\ \sf\bull\longmapsto -128$